If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2^x=4^x+3
We move all terms to the left:
2^x-(4^x+3)=0
We get rid of parentheses
2^x-4^x-3=0
We move all terms containing x to the left, all other terms to the right
2^x-4^x=3
| 25^x=125^x-5 | | 8-(2x-1)=8 | | -2(3x+1)=-6x+7 | | 2x^2+4=5x-7 | | y+2=-4y-8 | | -11=s/2 | | 7u+2u=81 | | d+6=-10 | | 7x+1÷9=2x÷3 | | -2(3x+5)=-37 | | f/4=-6 | | 3-3x-4x=-4 | | 3x-9=4x+20 | | 5k+8=-52 | | 0=0.02x^2+12x-11 | | a➗5+5=14 | | 2t5−75=125 | | -9=-5+z | | 2/3x-12=40 | | -3(2x-5)+1=4 | | 8x=5x/9 | | (2x^2+3x-2)(5-6x-4x^2)=-5(2x^2+3x+2) | | 2/3*x-12=40 | | 4+8y=-44 | | 3•x-5=2•x= | | 8+1/2/x=5 | | -6h=54 | | 6/7z=48 | | 1/2n+7=n+14 | | 4m+9m=-5 | | 6x+7=13-x | | (5x-2)(4x+7)-(5x-2)(5x-2)=0 |